Wednesday, December 14, 2011

Evaluate the indefinite integral.?

Substitute u = 2x^2 − 6x + 2, du = (4x − 6) dx. The integrand then becomes 1/(2u^4) du, which can be integrated to −1/(10u^5) + C, where C is an arbitrary constant. Reversing the substitution gives a final answer of −1/(10(2x^2 − 6x + 2)^5) + C.

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